The starting system of equations is {((x3)^2(y2)^2=16),(2x2y=10) } First step is to divide the second equation by 2 to get only x and y without coefficients {((x3)^2(y2)^2=16),(xy=5) } Now we can calculate one of the variables from the second equation to substitute it in the first one {((x3)^2(y2)^2=16),(y=5x) } If we substitute we get (x3)^2(**5x**2)^2=16 (x3)^2(7x)^2=16 x^26xxx^216=0 2x^2x42=0 Now we can divide both sides by 2 x^2Start your free trial In partnership with You are being redirected to Course Hero I want toSteps for Solving Linear Equation x = 2 y 5 x = 2 y − 5 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2y5=x 2 y − 5 = x Add 5 to both sides Add 5 to both sides
State The Type Of The Quadratic Surface X 3 2 Y 5 2 Z 8 2 1 Choose From The Following Options 1 Ellipsoid 2 Hyperboloid Of One Sheet 3 Hyperboloid Of Two Sheets 4 None Of These Study Com
X^2+(x+3)(2x-y+5)=x+16
X^2+(x+3)(2x-y+5)=x+16-2x3y316x2y432xy5 Final result 2xy3 • (x 4y)2 Step by step solution Step 1 Equation at the end of step 1 (((2•(x3))•(y3))((16•(x2))•(y4)))25xy5(3*x5)^2(16)=0 Step by step solution Step 1 11 Evaluate (3x5) 2 = 9x 230x25 Step 2 Pulling out like terms 21 Pull out like factors 9x 2 30x 9 = 3 • (3x 2 10x 3) Trying to factor by splitting the middle term 22 Factoring 3x 2 10x 3 The first term is, 3x 2 its coefficient is 3
Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreMinimize z = x 3y 2u5z 5y 2x 2 > Subject to y 2 ALALALALAL 16 16 5 0 C y 0 Minimum is at 2= y = > Next Question Get more help from Chegg Solve itSystemofequationscalculator xy=2, 2x5y=16 en Related Symbolab blog posts High School Math Solutions – Systems of Equations Calculator, Elimination A system of equations is a collection of two or more equations with the same set of variables In this blog
Calculadoras gratuitas passo a passo para álgebra, trigonometria e cálculoGraph ( (x3)^2)/16 ( (y5)^2)/9=1 (x − 3)2 16 (y 5)2 9 = 1 ( x 3) 2 16 ( y 5) 2 9 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requires the right side of the equation be 1 1X = (3 − y) (y 5) − 5, y ≥ −5 and y ≤ 3 View solution steps Steps by Finding Square Root ( x 5 ) ^ { 2 } ( y 1 ) ^ { 2 } = 16 ( x 5) 2 ( y 1) 2 = 1 6 Subtract \left (y1\right)^ {2} from both sides of the equation Subtract ( y 1) 2 from both sides of the equation
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyStep by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method 2x3y=5;5x−2y=−16 Tiger Algebra SolverGraph ((x5)^2)/4((y3)^2)/16=1 Simplify each term in the equation in order to set the right side equal to The standard form of an ellipse or hyperbola requires the right side of the equation be This is the form of an ellipse
Steps for Solving Linear Equation 2x3y = 5 2 x 3 y = 5 Subtract 3y from both sides Subtract 3 y from both sides 2x=53y 2 x = 5 − 3 y Divide both sides by 2 Divide both sides by 2Move all terms containing x to the left, all other terms to the right Add 'y' to each side of the equation 3x 1y y = 16 y Combine like terms 1y y = 0 3x 0 = 16 y 3x = 16 y Divide each side by '3' x = y Simplifying x = yAlgebra Write the Equation in Standard Form y= (x5)^216 y = (x − 5)2 16 y = ( x 5) 2 16 To write an equation in standard form, move each term to the right side of the equation and simplify y = ax2 bxc y = a x 2 b x c Simplify (x −5)2 16 ( x 5) 2 16
2(5) 3y = 16 10 3y = 16 3y = 6 y = 2 So our solution is (5,2) or ELIMINATION METHOD xy =3 2x3y=16 I'm going to eliminate the y Multiply the top equation by 3 3(xy = 3) 2x3y = 16Simplify 3x3y=9 2x3y=16 Add the two equations together 5x 0y = 25 x = 5 Then substitute x=5 back into one of the original equations, let's use theOur online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!In the twodimensional coordinate plane, the equation x 2 y 2 = 9 x 2 y 2 = 9 describes a circle centered at the origin with radius 3 3 In threedimensional space, this same equation represents a surface Imagine copies of a circle stacked on top of each other centered on the zaxis (Figure 275), forming a hollow tube
Start your free trial In partnership with You are being redirected to Course Hero I want to submit the same problem to Course Hero CancelSolution for y2=35(x5) equation Simplifying y 2 = 35(x 5) Reorder the terms 2 y = 35(x 5) Reorder the terms 2 y = 35(5 x) 2 y = (5 * 35 x * 35) 2 y = (175 35x) Solving 2 y = 175 35x Solving for variable 'y' Move all terms containing y to the left, all other terms to the rightMaximize 5 3x 4y x^2 x y y^2 WolframAlpha Have a question about using WolframAlpha?
The centre of the ellipse #(xh)^2/a^2(yk)^2/b^2=1# is #(h,k)# The two axes are #2a# and #2b# and major axis is the greater of the two Vertices are #(ha,k)# and #(h,kb)# Here those along major axis are called vertices and those along minor axis are called covertices #(x2)^2/16(y5)^2/=1# can be written as #(x2)^2/4^2(y5)^2The original circle is centered at (3,5) with a radius of 4 Reflecting across the y=2 shifts the y coordinate of the center The center is 3 units above the line y=2 The reflected circle will have the center 3 units below the line y=2 I leave it to you to determine the sumRearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation (x3)*2 (y5)*2 (16)=0
Trigonometry Graph (x3)^2 (y5)^2=16 (x − 3)2 (y − 5)2 = 16 ( x 3) 2 ( y 5) 2 = 16 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard form The variable r r represents the radius of the circle, h h represents the xoffset from the origin, and k kFirst type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More Examples a) compared to the graph of f=1/x the grapg of y=3/x4 is vertical stretch by factor of 3 and a translation of 4 units left b) compared to the graph of y=1/x the graph of 3/x4 is a math The graph of y=x^2 is transformed by a stretch of scale factor 2 parallel to the x axis, followed by a translation of (0 3)
Polynomial Roots Calculator 23 Find roots (zeroes) of F (x) = x32x216x16 Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F (x)=0 Rational Roots Test is one of the above mentioned tools It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers11 The equation of a circle is (x 3)2 y2 8 The coordinates of its center and the length of its radius are 12 The equation of a circle is (x 2)2 (y 5)2 32 What are the coordinates of the center of this circle and the length of its radius?Y=3 (x5) (x2) Simple and best practice solution for y=3 (x5) (x2) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it
2^x 3^y = 5 2^x2 3^y1 = 18 Which can be written as 2^x2^2 3^y3^1 = 18 42^x 33^y = 18 Now, let's assume 2^x =m 3^y=n So, when we replace the above, we get two equations mn=5 4m3n=18 On solving the simultaneous equations, we get m=3 n=2 Now, 2^x = 3 x = log 3 to the base 2 x = log 3/log 2 x= 158 3^y=2 y = log 2 to the base 3 Explanation This equation can be recognised as the standard equation for a circle, which is (x −h)2 (y −k)2 = r2, where (h,k) is the centre of the circle and r is the radius The example is therefore a circle with centre ( −3, − 5) and radius 4 Answer linkCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
16 Suppose the relationship between variables Y, X, Xz and U is given by the following model Y = 52 (X2)2 3 X2 U U Uniform(1 X X2,1 X X2) X1 Uniform(0,2) X, Uniform(04) Answer the following questions (explaining your answers), or do what is asked 1 Transcript Example 17 Solve the pair of equations 2/𝑥 3/𝑦=13 5/𝑥−4/𝑦=−2 2/𝑥 3/𝑦=13 5/𝑥−4/𝑦=−2 So, our equations become 2u 3v = 13 5u – 4v = –2 Hence, our equations are 2u 3v = 13 (3) 5u – 4v = – 2 (4) From (3) 2u 3v = 13 2u = 13 – 3V u = (13 − 3𝑣)/2SOLUTION The graph of (x3)^2 (y5)^2=16 is reflected over the line y=2 The new graph is the graph of the equation x^2 Bx y^2 Dy F = 0 for some constants B, D, and F Find BDF
Graph (x3)^2 (y1)^2=16 (x − 3)2 (y − 1)2 = 16 ( x 3) 2 ( y 1) 2 = 16 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match the values in this circle to those of the standard formNow, applying the Square Root Principle to Eq #321 we get x5 = √ 16 Subtract 5 from both sides to obtain x = 5 √ 16 Since a square root has two values, one positive and the other negative x 2 10x 9 = 0 has two solutions x = 5 √ 16 or x = 5 √ 16 Solve Quadratic Equation using the Quadratic Formula 33 Solving x 2Circleequationcalculator center (x2)^2(y3)^2=16 en Related Symbolab blog posts My Notebook, the Symbolab way Math notebooks have been around for hundreds of years You write down problems, solutions and notes to go back
X^3 x^2 y x y^2 y^3 Extended Keyboard;13 Circle O is represented by the equation (x 3)2 (y 5)2 48 The coordinates of the (x a)^2 (y b)^2 = r^2 where (a,b) = the point where the center of the circle lies r = radius From the equation, (x 3)^2 (y 5)^2 = 16 r^2 = 16 r = 4 units Recall that the circumference of a circle is given by C = 2*pi*r Substituting, C = 2*314*2 C
Move all terms containing x to the left, all other terms to the right Add '15' to each side of the equation 15 15 6x = 16 15 Combine like terms 15 15 = 0 0 6x = 16 15 6x = 16 15 Combine like terms 16 15 = 31 6x = 31 Divide each side by '6' x = Simplifying xSimple and best practice solution for 3(3x2)=165x equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, soGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
1) The graph of (x3)^2 (y5)^2=16 is reflected over the line y=2 The new graph is the graph of the equation x^2 Bx y^2 Dy F = 0 for some constants B, D, and F Find BDF 2) Geometrically speaking, a parabola is defined as the set of points that are the same distance from a given point and a given lineCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music2 3\pi e x^{\square} 0 \bold{=} Go Related » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
2 x 3 2 y k 2 r 2 x h 2 16 9 r2 25 r2 5 ry 5 2 5 2 x 3 2 y 5 2 25 x 3 2 General from MATH SECTION 1 at Anderson High School, CincinnatiThe circle (x 3)^2 (y 5)^2 = 16 can be drawn with parametric equations Assume the circle is traced clockwise as the parameter increases If x = 3 4 cos t then y = Get more help from Chegg Solve it with our calculus problem solver and calculator To convert from Cartesian to Polar coordinates use the following formulae that link them ∙ x = rcosθ and y = rsinθ x2 y2 − 8y 16 = 16 (expanding bracket) ⇒ r2cos2θ r2sin2θ − 8rsinθ 16 −16 = 0 then r2(cos2θ sin2θ) − 8rsinθ = 0 using the identity cos2θ sin2θ = 1 ⇒ r2 = 8rsinθ and dividing both sides by r