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5/x-3/y=1 3/2x+2/3y=5 by substitution method-WebSolve an equation, inequality or a system Example 2x1=y,2y3=x 1 2 3 4 5 6 7 8 9 0, < > ≤ ≥ ^ √ ⬅ F _ ÷ (* / ⌫ A ↻ x y = GWebThe vertices B and C of a ABC lie on the line, x 2/3= y 1/0= z /4 such that BC =5 units Then the area in sq units of this triangle, given that the point A 1, 1,2, isA 5 √17B √34C 6D 2

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WebTo solve by substitution, you first need to isolate one of the variables in one equation by itself on one side the equation Let's isolate the x in the second equation x2y=14 Subtract 2yWebSimultaneous Quadratic Equations x2 y2 − 2x 6y− 35 = 0 and 2x3y = 5 https//mathstackexchangecom/q/ From the second equation, we have that x =WebAlgebra Solve by Graphing y=2x3 y=2x5 y = 2x − 3 y = 2 x 3 y = −2x 5 y = 2 x 5 Create a graph to locate the intersection of the equations The intersection of the system of

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Incoming Term: 5/x-3/y=1 3/2x+2/3y=5, 5/x-3/y=1 3/2x+2/3y=5 by elimination method, 5/x-3/y=1 3/2x+2/3y=5 by substitution method, 23. (5)/(x)-(3)/(y)=1 (3)/(2x)+(2)/(3y)=5 (x =0 y =0), (ii) (3)/(2x)+(2)/(3y)=5 (5)/(x)-(3)/(y)=1,
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