The starting system of equations is {((x3)^2(y2)^2=16),(2x2y=10) } First step is to divide the second equation by 2 to get only x and y without coefficients {((x3)^2(y2)^2=16),(xy=5) } Now we can calculate one of the variables from the second equation to substitute it in the first one {((x3)^2(y2)^2=16),(y=5x) } If we substitute we get (x3)^2(**5x**2)^2=16 (x3)^2(7x)^2=16 x^26xxx^216=0 2x^2x42=0 Now we can divide both sides by 2 x^2Start your free trial In partnership with You are being redirected to Course Hero I want toSteps for Solving Linear Equation x = 2 y 5 x = 2 y − 5 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2y5=x 2 y − 5 = x Add 5 to both sides Add 5 to both sides
State The Type Of The Quadratic Surface X 3 2 Y 5 2 Z 8 2 1 Choose From The Following Options 1 Ellipsoid 2 Hyperboloid Of One Sheet 3 Hyperboloid Of Two Sheets 4 None Of These Study Com
X^2+(x+3)(2x-y+5)=x+16